the half life of a first order reaction is 100 sec.what is the time required for 90% completion of reaction?
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Answer:
k (rate constant)=0.693/100s=6.93*10^-3s^-1
t90%=( 2.303/k) *log(1/(10/100))= (2.303/k) * log10=2.303 /k sec=332.32sec
log10=1(i.e log 10 to the base 10 is 1)
Explanation:
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