The hcf and lcm of two number is 12 and 72 respectively if the sum of these two number is 60 then find the another number
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Let the two numbers be x and y.
We know that.. product of two numbers = HCFx LCM.
Therefore XY= 12 x 72= 864..(1)
According to given condition, their sum is 60
Therefore x+y 60. .(2)
We know that
(x-y)? =(x+y)2 -4xy
Substitute values from 1 & 2
(X-y)2 = 3600-4x864=144
X-Y =v144= 12...(3)
By solving 2 and 3
We get x=36 and y=24........ THANKU
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