Math, asked by krishnapriyakaku4, 2 days ago

The HCF of 2 ^ 3 * 3 ^ 2 * 5 * 7 ^ 4,2 ^ 2 * 3 ^ 5 * 5 ^ 2 * 7 ^ 3 and 2 ^ 3 * 5 ^ 3 * 7 ^ 2 is:​

Answers

Answered by UTTAMSHARMA84
1

Answer:

H.C.F is 2^2*5*7^2

I hope it's helpful to you

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