The HCF of two numbers is 23 and the LCM is 1449. If one number is 207 the other one will be
Answers
Answered by
5
heya..
a=161
HCF=23
LCM=1449
we know that
a×b=HCF×LCM
161×b=23×1449
b=23×1449/161
b=33327/161
b=207
tysm.#gozmit
a=161
HCF=23
LCM=1449
we know that
a×b=HCF×LCM
161×b=23×1449
b=23×1449/161
b=33327/161
b=207
tysm.#gozmit
Answered by
4
Hey mate!
Here's your answer!!
Let x be the other number.
Given that the HCF ( x , 161) = 23...............(1)
Given that x and 161 has the LCM = 1449.......(2).
We know that LCM (x , 161) = x×161/(HCF)
So, x × 161/23 = 1449
x = 1449 × 23/161
x = 207
Therefore the other number is 207.
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
Let x be the other number.
Given that the HCF ( x , 161) = 23...............(1)
Given that x and 161 has the LCM = 1449.......(2).
We know that LCM (x , 161) = x×161/(HCF)
So, x × 161/23 = 1449
x = 1449 × 23/161
x = 207
Therefore the other number is 207.
✌ ✌ ✌
#BE BRAINLY
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