The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.
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Answer:
Given, HCF=23
LCM=1449
Let the two numbers be a and b. Let a=161. We have to find b.
We know that
HCF(a,b)×LCM(a,b)=a×b
⇒23×1449=161×b
⇒23×1611449=b
⇒b=23×9
∴b=207
Thus, the other number is 207.
Step-by-step explanation:
Hope this may help you
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