Question

THE HCF OF TWO NUMBERS IS 27 AND THEIR LCM IS 162. IF ONE OF THE NUMBERS IS 54, FIND THE OTHER NUMBER?

Answer 1

L.C.M*H.C.F= product of 2 no.
27*162=54*x
x=27*162/54
x=81

Answer 2

Let the other side be y
HCE×LCM=54×y
27×162=54×y
4374=54×y
4374/54=y
81=y