Question

The HCF of two numbers is 69 and their LCM is 63. Find their product.

Answer 1

Answer:

We know,Product of two numbers =HCF×LCM

Step-by-step explanation:

Let the two numbers be a and b

Therefore,Product of a and b =69×63

= 4347

Hence,the required product is 4347.

Answer 2

✪ANSWER✪

• The given condition is not satisfied by any two numbers(LCM cannot be less than HCF).
• If the values were interchanged by typing mistake, then when HCF = 63 and LCM = 69, product of two numbers = 4347.

★EXPLAINATION★

FIRST PART

• As HCF is a factor of both numbers, HCF will be always less than or equal to the numbers.

HCF ≤ a, b

• As LCM is a multiple of both numbers, LCM will be always greater than or equal to the numbers.

LCM ≥ a, b

• As such LCM ≥ HCF. The given data in the question does not satisfy this condition and hence there is no number and their product.

SECOND PART

If two numbers a, b has Lowest common multiple L = 69 and Highest common factor, H = 63, (Here L > H) then

a x b = L x H

⇒ a x b = 69 x 63

⇒ a x b = 4347