Question

The hcf of two numbers is 8100 if p=2^3.3^x.5^4 and Q=2^Y.3^6.5^Z THEN FIND THE VALUE OF XYZ

Answer 1

Answer:16

Step-by-step explanation:the prime factorisation of 8100: 3^4 • 5^2 • 2^2

3^4 = 3^x

Therefore  x=4

2^2 = 2^y

Therefore y= 2

5^2 = 5^z

Therefore z=2

      Thus xyz = 4•2•2

                      = 16

     

Answer 2

xyz = 16

see image for solution

cheese

:)