The height attained by projectile projected at
V is H. If the speed of projection is tripled
keeping other parameters constant. The
maximum height attained will be:
(a) H
(b) 2H
(C) 3H
(d) 9H
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Answer:
As per formulae H directly proportional to u²
so when u is thrice then H will be 9times of initial
so answer is 9H
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