Question

The height corresponding to the longest side of the triangle whose sides are 91 cm, 98 cm and 105 cm in length is

Answer 1

here is ur answer mate,

hb=84cm

Using the formulas

A=hbb

2

A=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving forhb

hb=﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4

2b=﹣914+2·(91·98)2+2·(91·105)2﹣984+2·(98·105)2﹣1054

2·98=84cm

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