Question

the height of a right triangle is 7 cm less than it base .if hypotenuse is 13 cm form quadratic equation to find the base of the triangle

Answer 1

Let x= length and y= breadth , z = hypotenuse As per condition, X-7= y, x= y+7 By Pythagoras formula,  Xsquare + ysquare = z square (Y+7)square + ysquare = xsquare Ysquare + 14y + 49 + ysquare = 169  2ysqaure + 14y - 120 = 0

Answer 2

let the base of triangle be x
so the hight is
$x - 7$

$13 {}^{2} = (7 - x) {}^{2} + x {}^{2}$
$169 = 49 + x {}^{2} - 2 \times 7 \times x$
$120 = x { }^{2} - 14x$
$x { }^{2} - 14x - 120$
$x {}^{2} + 6x - 20x - 120 = 0$
$x(x + 6) - 20(x + 6)$
$(x - 20)(x + 6)$
X=20 cm

this is the answer frnd