The height of the unbroken part is 15m and the broken part of the tree has fallen at
20m away from the base of the tree.Using the Pythagoras property answer the
following questions:. What is the length of the broken part?
i) 15m ii) 20m iii) 25m iv) 30m
2) In the formed right angled triangle, which side/sides considered as altitude?
i) 15m ii) 20m iii) both 15m and 20m iv) none of these
3) What is the height of the full tree?
i) 40m ii) 50m iii) 35m iv) 30m
Answers
the answer of the question is 20 ok mam or sir
Given:
The height of the unbroken part is 15m and the broken part of the tree has fallen at 20m away from the base of the tree.
To find:
What is the length of the broken part?
i) 15m ii) 20m iii) 25m iv) 30m
2) In the formed right-angled triangle, which side/sides considered as altitude?
i) 15m ii) 20m iii) both 15m and 20m iv) none of these
3) What is the height of the full tree?
i) 40m ii) 50m iii) 35m iv) 30m
Solution:
Let's assume,
"AB" → the height of the unbroken part of the tree = 15 m
"AC" → the height of the broken part of the tree
"BC" → the distance between the base of the tree and the top of the broken part of the tree = 20 m
Case (1): Finding the length of the broken part:
Applying the Pythagoras theorem to the formed right-angled triangle ABC, we get
Thus, the length of the broken part of the tree is → option (iii) → 25 m.
Case (2): Finding which side is the altitude:
In right-angled triangle ABC, we have
→ "AB" which is the unbroken part of the tree is the altitude
→ AB = 15 m
→ Therefore, side measuring 15 m is considered as the altitude.
Thus, in the formed right-angled triangle, side measuring 15 m (option (i)) is considered as altitude.
Case (3): Finding the height of the full tree:
The height of the full tree is,
= AB + AC
= 15 m + 25 m
= 40 m
Thus, the height of the full tree is → option (i) → 40 m.
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