The horizontal distance between two towers is 150m.the angle of elevation of the top of the first tower when seen from the top of the second tower is 30.if the height of the second tower is 50m.find the height of the first tower.
Answers
Given : Two towers are 150 m apart.
The angle of elevation of the top of the first tower as seen from the top of the second tower is 30°
To : Find the height of the
First tower, when the second tower is 50 m high
Solution:
Let say h is the height of first tower more than tower 2
Tower 1 height = tower 2 height + h
d = horizontal distance between towers = 150 m
Tan 30° = h / d
=> 1/√3 = h / 150
=> h = 50√3
=> h = 86.6 m taking √3 = 1.732
height of the First tower, when the second tower is 50 m high
= 50 + 86.6
= 136.6 m
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