Question

The horizontal distance between two Towers is 60m the angle of depression of the top of the first Tower when seen from the top of the second Tower is 30° if the height of the second Tower is 90m find the height of the first Tower.
USE ROOT 3= 1.732

Answer 1

Step-by-step explanation:

Let AB and CD be the two towers

Height of the second tower, AB =150m and

Distance between two towers BD =60m

Let's assume the height of the first tower is h m.

We know, In right angled △,

tan(Θ)=

Adjacent

Opposite

tan30

0

=

EC

AE

tan30

0

=

60

150−h

.....[AE=AB-ED] and [EC=BD=60]

⇒

3

1

=

60

150−h

⇒h

3

=150

3

−60

⇒h=150−20

3

The height of the first tower is 150−20

3

m.