Question

the hypotenuse of a right angled triangle 1 cm more than twice the shortest side.if the third side is 2 cm less than the hypotenuse, find the sides of the triangle

Answer 1

Let shortest side is( B) X

Hypotenuse(H) =2X+1

Other side(L) = 2X+1-2

H^2= L^2 +B^2

(2X+1)^2 =( 2X-1)^2 + X^2

4X^2 +4X+1 =4X^2-4X+1 +X^2

X^2=8X

X=8

So the sides of the triangle are

8,17,15