Question

The increasing order of molarity with 25 gm each of NaOH, LION, AI(OH)S, KOH, B(OH)8 In
same volume of water?
(a) Al(OH)3 <B(OH)3 < KOHNaOH <LIOH
(b) LIOH < NaOH KOH <B(OH)3< Al(OH)3
(c) LIOH < NaOH <B(OH)3< KOH < Al(OH)3
(d) NaOH <LIOH <B(OH)3 < Al(OH)3 < KOH​

Answer 1

Explanation:

same value 13+12=°`••√√π

Answer 2

Answer:

The correct option is (a).

Explanation:

$Molarity=\frac{mole \ of \ compound}{Volume \ of \ solvent \ (L)}\\Molarity=\frac{Mass \ of \ given \ compound }{Molecular \ mass \ of \ compound\times Volume \ of solvent \ (L)}$

Given that the mass of each compound is 25gm.

The volume of water is also the same for each compound.

Molarity depends on the molecular mass of compounds. Higher the value of molecular mass lower will be molarity.

Molecular mass of $Al(OH)_3$ = 78g/mol

Molecular mass of LiOH = 23.95g/mol

Molecular mass of NaOH = 39.99g/mol

Molecular mass of $B(OH)_3$ = 68.83g/mol

The order of the molecular mass of given compounds is:

$Al(OH)_3 > B(OH)_3 > NaOH > LiOH$

order of increasing molarity is:

$Al(OH)_3 < B(OH)_3 < NaOH < LiOH$

Therefore, the correct option is (a)