The initial velocity of an object is 8m/s . This object is moving with an acceleration of 4m/s^2. Find the velocity of the object and distance covered after 6 second
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u=8m/s
a=4m/s^2
V when time =6s
V=u+at
V=8+4×6
V=8+24
V=32m/s
s when time is 6s
s=ut+1/2at^2
s=8×6+1/2×4×6^2
s=24+2×36
s=24+72
s=96m
a=4m/s^2
V when time =6s
V=u+at
V=8+4×6
V=8+24
V=32m/s
s when time is 6s
s=ut+1/2at^2
s=8×6+1/2×4×6^2
s=24+2×36
s=24+72
s=96m
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