Question

The fraction of a floating object of volume v0 and density d0 above the surface of a liquid of density d will be

Answer 1

Hello dear,

● Answer: 1 - d0/d

● Explanation-
Let V0 be volume of the object and V be that for immersed part.

For an object to float-
Buoyanct force by immersed object = Weight of object
d.V.g = d0.V0.g
V = d0.V0/d

Volume of object outside water-
V' = V0 - V
V' = V0 - V0.d0/d
V' = V0 (1-d0/d)

Fraction of outside part to total volume-
V' / V0 = V0(1-d0/d) / V0
V' / V0 = 1 - d0/d

Fraction of floating part to overall volume is 1-d0/d.

Hope that is helpful...

Answer 2

Explanation:

please mark as brainliest friend and follow me