Question

the interior angle of a regular polygon with ‛n' sides​

Answer 1

$\huge\star\underline{ \underline \pink {\mathfrak{answer}}} \star$

We know that if a polygon has 'n' sides, then it is divided into (n – 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles. Thus, each interior angle of the polygon = (2n – 4)/n right angles.

$\textbf{Hope\: it\: helps\: you\: ❤️ }$

Answer 2

We know that if a polygon has 'n' sides, then it is divided into (n – 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles. Thus, each interior angle of the polygon = (2n – 4)/n right angles.

Hope it helps ❣️

25 ❣️- inbix