Question

The internal resistance of a battery of 2 V terminal voltage is 0.2 Ω. If the current flowing through the battery is 0.5 A, what will he the emf of battery ?

Answer 1

Answer:

emf of battery  = 2.1 V

Explanation:

V = E - Ir

E = EMF of Battery

V = Terminal Voltage

I =  Current

r = internal Resistance

internal resistance of a battery is 0.2 ohm

=> r = 0.2 ohm

2 V terminal voltage

=> V = 2V

current flowing through the battery is 0.5 A

I = 0.5 A

putting all these values in

V = E - Ir

2 = E - (0.5)(0.2)

=> 2 = E - 0.1

=> E = 2.1 V

hence emf of battery will be 2.1V

emf of battery  = 2.1 V

Answer 2

Answer:

Explanation:

Refer the below attachment.