Question

The internal resistance of a cell of E.M.F 2 volt is 0.1 ohm.It is connectedto an external resistance 0.9ohm .what will be the current through the circuit

Answer 1

Given EMF(∈) of the cell =2V

we know that ∈=IR+Ir

WHERE

I= current flowing through the circuit

R=external resistance offered to the current

r=internal resistance of the battery

hence substituting the values

we get

∈=I(R+r)

2=I(0.9+0.1)

2=I$\times$1

I=2A