the internal resistance of a cell of emf 2V is 0.1 ohm it is connected to a resistance of 0.9 ohm the voltage across the cell will be A.0.5V B. 1.8V C. 1.95V D. 3V
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Given;
- V1 = 2V
- R1 = 0.1Ω
- R2 = 0.9Ω
- V2 = ?
Thus by ohm's law ;
- V1 = IR1
- 2 = I × 0.1
- I = 2/0.1
- I = 20A
Thus by ohm's law in the second case;
- V2 = IR2
- V2 = 20 × 0.9
- V2 = 180/10
- V2 = 18 V.
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