The intersecting point of two linear equations 5x-4y+8=0,7x+6y-9=0
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5x - 4y = -8------(i)
7x + 6y = 9 ------(ii)
(5x - 4y = -8)3
(7x + 6y = 9)2
then
15x - 12y = -24-----(iii)
14x +12y = 18------(iv)
_____________
29x = -6
x = -(6/29)
by 1st equation
5x - 4y = -8
5(-6/29) -4y = -8
-30/29 -4y = -8
4y = 8 - 30/29
4y = 202/29
y = 202-116 = 101/58
so x = -(6/29)
y = 101/58
i hope it will help you
regards
7x + 6y = 9 ------(ii)
(5x - 4y = -8)3
(7x + 6y = 9)2
then
15x - 12y = -24-----(iii)
14x +12y = 18------(iv)
_____________
29x = -6
x = -(6/29)
by 1st equation
5x - 4y = -8
5(-6/29) -4y = -8
-30/29 -4y = -8
4y = 8 - 30/29
4y = 202/29
y = 202-116 = 101/58
so x = -(6/29)
y = 101/58
i hope it will help you
regards
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