The ionic radii of s^2 and te^2 are 1.84 and 2.21 angustrum respectively. the ionic radii of se^2 is
a.1.83A. b.2.22A. c.4.5A d. 2.02A
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Answered by
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The radius increases while moving down the group.
In a group, S Se Te is the form of increasing radius.
Thus the radius of Se should be in between the radius of S and Te.
Thus, the ionic radius of Se 2 = 2.02 A
______________________________
Thus option d is the required answer.
______________________________
Hope this is what you were looking for.
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In a group, S Se Te is the form of increasing radius.
Thus the radius of Se should be in between the radius of S and Te.
Thus, the ionic radius of Se 2 = 2.02 A
______________________________
Thus option d is the required answer.
______________________________
Hope this is what you were looking for.
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Answered by
18
Solution: Ionic Radii of Se^2- = (1.84 + 2.21)/2 = 2.02 A
Explanation: Ionic radius of Se^2− is expected to be in between the ionic radii of S^2− and Te^2−
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