Question

The ionization energy of a hydrogen atom is 13.6eV. The energy of the third-lowest electronic level in doubly ionized lithium (Z = 3) is - (D A A ll​

Answer 1

The ionisation energy of a hydrogen atom is 13.6 eV. means, amount of energy required to remove an electron from an isolated gaseous hydrogen atom is 13.6 eV.

according to Bohr's theory,

energy of electron in nth orbit is given by, E = -13.6 × Z²/n²

here Z is atomic number and n is orbit number.

here, Z = 3 [ atomic number of Lithium is 3 ]

and n = 3 [a/c to question, we have to find energy of third lowest electronic level.]

so, E = -13.6 × (3)²/(3)² = -13.6eV

hence, the energy of the third lowest electronic level in doubly ionised lithium is -13.6eV.

Answer 2

Answer:

The ionisation energy of a hydrogen atom is 13.6 eV. means, amount of energy required to remove an electron from an isolated gaseous hydrogen atom is 13.6 eV.

according to Bohr's theory,

energy of electron in nth orbit is given by, E = -13.6 × Z²/n²

here Z is atomic number and n is orbit number.

here, Z = 3 [ atomic number of Lithium is 3 ]

and n = 3 [a/c to question, we have to find energy of third lowest electronic level.]

so, E = -13.6 × (3)²/(3)² = -13.6eV

hence, the energy of the third lowest electronic level in doubly ionised lithium is -13.6eV.

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