Question

The king, queen and jack of diamonds are removed from a pack of 52 playing cards and the pack is well shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of (i) diamond (ii) a jack .

Answer 1

King, queen and jack of Diamonds are removed from a deck of 52 playing cards.
So remaining cards in a deck= 52 -3=49

Total number of outcomes = 49

i) We know that there are 13 cards of diamond. After removing king, queen and jack of Diamonds only 10 Diamond cards are left in a Deck.
Number of favourable Outcomes= 10

Probability = Number of favourable outcomes/ Total number of outcomes
Required probability = P(Diamond cards)= 10/49

ii) There are four Jacks in a deck. After removing a jack of diamond we left with 3 Jacks.
Number of favourable outcomes = 3

Probability = Number of favourable outcomes/ Total number of outcomes
Required probability = P(Jack)= 3/49.

HOPE THIS WILL HELP YOU...

Answer 2

Heya Frnd...........☺

3 cards are removed ; therefore,

✴ 52 - 3 = 49 cards are left ✴

Now,

Total no. of outcomes = 49

1 ) a card of diamond........

Total no. of diamond cards left = 10

Total outcomes = 49

So, probability = 10/49 ..............#ANS 1 #

2 ) A Jack .........

Total no. of jacks left = 3

Tot. no. of outcomes = 49

So,

Probability = 3/49 ..............# ANS 2 #

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