The largest cone is curved out from one face of solid cue of side 21 cm. find the volume of remaining solid.
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Solution -
side of cube= 21 cm
ATQ,
side of cube=diameter of largest cone curved out=21cm
and height of cone = 21/2cm
volume of cone= 1/3 x pi x r^2 x h
=2404.86cm3(by taking pi as 3.14)
volume of cube=21^3=9261 cm3
so the volume of remaining solid = volume of cube-volume of cone
9261 cm3-2404.86 cm3=6856.14 cm3
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side of cube= 21 cm
ATQ,
side of cube=diameter of largest cone curved out=21cm
and height of cone = 21/2cm
volume of cone= 1/3 x pi x r^2 x h
=2404.86cm3(by taking pi as 3.14)
volume of cube=21^3=9261 cm3
so the volume of remaining solid = volume of cube-volume of cone
9261 cm3-2404.86 cm3=6856.14 cm3
Kindly mark it as brainleist
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