Question

the largest number of molecule present between 3.6 gram of H20 4.8 gram of C2H5OH 2.8 gram of CO and 5.4 gram of N2O5

Answer 1

Answer:

The correct and simple answer is the largest number of molecules present in 3.6gm of H20.

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Answer 2

Answer : $3.6 g$ of $H_{2} O$ contains the largest number of molecules.

Explanation:

the largest number of molecule present between 3.6 gram of H20 4.6 gram of C2H5OH 2.8 gram of CO and 5.4 gram of N2O5?

To calculate the number of molecules:

$No. of molecules = \frac{given mass }{molecular mass} * Avogadro's number$

No. of molecules in $3.6 g$ of $H_{2} O$ = $\frac{3.6}{18}* N_{A} = \frac{N_{A} }{5}$

No. of molecules in $4.6 g$ of $C_{2} H_{5} OH$ = $\frac{4.6}{46}* N_{A} = \frac{N_{A} }{10}$

No. of molecules in $2.8 g$ of CO = $\frac{2.8}{28}* N_{A} = \frac{N_{A} }{10}$

No. of molecules in $5.4 g$ of $N_{2} O_{5}$ = $\frac{5.4}{108}* N_{A} = \frac{N_{A} }{20}$

$3.6 g$ of $H_{2} O$ contains the largest number of molecules.

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