Question

The last digit of the value of the number 2003²⁰⁰² + 2001²⁰⁰² is.....

with solution​

Answer 1

Answer:

Last digit of (3)^4×n+2=9 

∴ last digit of (2003)^4×500+2  is 9

And last digit of 2001²⁰⁰² =1

Therefore last digit of 2003²⁰⁰²+2001²⁰⁰² is 0    ( as 1+9=10)

Step-by-step explanation:

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Answer 2

Answer:

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