Question

the lcm and hcf of two no are 504 and 18respectively find the other no if one no is126

Answer 1

Given:

LCM = 504

HCF = 18

One number= 126

To Find :

The other number

Solution:

Let the other number be N

Product of two numbers = LCM x HCF

According to the question:

=> N x 126 = 504 x 18

=> 126N = 9072

=> N = 9072/126

=> N = 72

The other number = 72

Verification:

Product of two numbers = LCM x HCF

72 x 126 = 504 x 18

9072 = 9072

Hence, The other number = 72