the lcm and hcf of two no are 504 and 18respectively find the other no if one no is126
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Given:
LCM = 504
HCF = 18
One number= 126
To Find :
The other number
Solution:
Let the other number be N
Product of two numbers = LCM x HCF
According to the question:
=> N x 126 = 504 x 18
=> 126N = 9072
=> N = 9072/126
=> N = 72
The other number = 72
Verification:
Product of two numbers = LCM x HCF
72 x 126 = 504 x 18
9072 = 9072
Hence, The other number = 72
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