the least area of circle circumscribing any right triangle of area 9/ is
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let r be the radius of the circle
ince, circle circumscribes right angled triangle
Therefore, diameter is the hypotenuse of the triangle ....[ prop. of semicircle]
let a & b be the other sides of the triangle
Therefore, a²+b²= (2r)²
we know that A.M≥G.M
so, a²+ b²/2≥√a²b²=ab
ab/2 ≤ r²
S ≤ r²
area of circle= πr² ≥πS
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