the least number which when divided by 12 15 20 and 54 leaves the same same reminder 8
Answers
Answer:
Step-by-step explanation:
Option B is correct.i.e., 548
Step-by-step explanation:
Given numbers are 12 , 15 , 20 , 54
To Find: least no. which is divided by given nos. and leaves remainder 8
Least no which is divisible by all given no is LCM of all nos.
LCM means least common multiple.
First we find LCM of 12 , 15 , 20 , 54 by prime factorization method
12 = 2 × 2 × 3
15 = 3 × 5
20 = 2 × 2 × 5
54 = 2 × 3 × 3 × 3
LCM( 12, 15 , 20 , 54 ) = 2 × 2 × 3 × 3 × 3 × 5 = 540
To find the required no. we add 8 to LCM
⇒ Required No. = 540 + 8 = 548
Thus, 548 is the least no which when divided by 12 15 20 and 54 leaves in each case a remainder of 8.
Therefore, Option B is correct.i.e., 548
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