Question

the lenght of the digonals of rhombus are 16 and 12 cm then the lenght of the sides of the rhombus is​

Answer 1

Answer:

12 cm×16 cm. = 96 sq.cm. Answer. Length of the side is the rhombus=√{(d1/2)^2+(d2/2)^2}.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

As the question mentioned there are 2 diagonals

The length of the first diagonal is 12 cm, whereas the length of the second diagonal is 16 cm

We divide the rhombus into 4 parts, let us take part 1:

As the diagram shown below, using Pythagoras theorem we find s

Now as we know that BD = 16 cm and AC = 12 cm; therefore to find S

We use,

Putting the values of BD and AC, we get,