Question

The length and breadth of a rectangle are in the ratio 10:7 its perimetee is 68 cm then find its area​

Answer 1

$\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$

Required answer:-

The required area of the rectangle is 280 cm².

Given Information:-

The length and breadth of a rectangle are in the ratio 10:7 and it's perimeter is 68 cm.

Need to find out:-

The required area of the rectangle = ?

Required Explanation:-

Let,

Length = 10y

Breadth = 7y

Perimeter = 68 cm

Formula used here:-

Perimeter of rectangle = 2 × (length + breadth)

Putting the values according to the given formula:-

=> 68 = 2 × (10y + 7y)

=> 68 = 2 × 17y

=> 68 = 34y

=> y = 68/34

=> y = 2 cm

So,

Breadth of a rectangle = 10 × 2

Breadth of a rectangle = 20 cm

Length of a rectangle = 7 × 2

Length of a rectangle = 14 cm

_____________________

Now, again formula used here:-

Area of rectangle = Length × Breadth

Putting the values according to the given formula:-

=> Area of rectangle = 20 × 14

=> Area of rectangle = 280 cm²

Hence:-

The required area of the rectangle is 280 cm².

Answer 2

Answer:

Required answer:-

The required area of the rectangle is 280 cm².

Given Information:-

The length and breadth of a rectangle are in the ratio 10:7 and it's perimeter is 68 cm.

Need to find out:-

The required area of the rectangle = ?

Required Explanation:-

Let,

Length = 10y

Breadth = 7y

Perimeter = 68 cm

Formula used here:-

Perimeter of rectangle = 2 × (length + breadth)

Putting the values according to the given formula:-

=> 68 = 2 × (10y + 7y)

=> 68 = 2 × 17y

=> 68 = 34y

=> y = 68/34

=> y = 2 cm

So,

Breadth of a rectangle = 10 × 2

Breadth of a rectangle = 20 cm

Length of a rectangle = 7 × 2

Length of a rectangle = 14 cm

_____________________

Now, again formula used here:-

Area of rectangle = Length × Breadth

Putting the values according to the given formula:-

=> Area of rectangle = 20 × 14

=> Area of rectangle = 280 cm²

Hence:-

The required area of the rectangle is 280 cm².

Step-by-step explanation:

$simple$

mark as brainlist answer