Question

The length and breadth of a rectangle are in the ratio 4 : 3. If its perimeter is 154 cm, find its length and breadth.

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Answer 1

Answer:

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

let the ratio be 4x and 3x

perimeter of rectangle..= 2(l+b)

154 = 2(4x + 3x)

154 = 14x

x = 154/ 14

x = 11

4x = 4× 11 = 44

3x = 3× 11 = 33.....

Answer 2

Step-by-step explanation:

Perimeter of rectangle = 100m

ratio of length is to breadth = 3:2 = 3x : 2x

Perimeter = 2(l+b)

P = 2(3x+2x)

= 6x + 4x = 10x

10x = 100 ; x = 100/10 = 10

l = 3x = 3 × 10 = 30 m

b = 2x = 2 × 10 = 20 m

Area of rectangle = length × breadth ( l×b )

A = 30 × 20 = 600 sq.m

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