The length and breadth of a square are increased by 40% and 30% respectively. the area of resulting rectangle exceeds the area of the square by
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Let x m. be the length of each side of a square . Its area = x^2 sq.units.
New length= x+(40/100).x= 7x/5 unit.
New breadth=x+(30/100).x=13x/10 unit.
New area =(7x×13x)/50 =(91x^2)/50 sq.unit.
Increase in area =91x^2/50- x^2 = (41x^2)/50sq.unit.
Percentage of increase in area= [ (41x^2)/50÷x^2 ]×100.=82 %. Answer.
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