Question

The length and the breadth of a rectangle are in the ratio of 3: 2. Find its sides, if its perimeter is 2,500 cm.​

Answer 1

Answer:

let us consider the length and breadth be x

formula:-p=2(length+breadth)

p=2500

length=3x and breadth=2x

by condition

2500=3x + 2x

2500=5x

x=2500÷5

x=500

now,

3x=3×500=1500

2x=2×500=1000

length is 1500 and breadth is 1000

Answer 2

Answer:

• Length of rectangle = 750 cm
• Breadth of rectangle = 500 cm

Explanation:

Given information,

The length and the breadth of a rectangle are in the ratio of 3:2. Find it's length and breadth, if its perimeter is 2,500 cm.

• Ratio of length and breadth = 3:2
• Perimeter of rectangle = 2500 cm
• Length and breadth of rectangle = ?

Let,

• Length of rectangle (L) = 3y
• Breadth of rectangle (B) = 2y

Using formula,

✪ Perimeter of rectangle = 2(L + B) ✪

Where,

• L denotes length of rectangle
• B denotes breadth of rectangle

We have,

• L of rectangle = 3y
• B of rectangle = 2y
• Perimeter of rectangle = 2500 cm

Putting all values,

➻ 2500 = 2(3y + 2y)

➻ 2500 = 2(5y)

➻ 2500 = 2 × 5y

➻ 2500 = 10y

➻ 10y = 2500

➻ y = 2500/10

➻ y = 250/1

➻ y = 250

Now,

◓ Length of rectangle = 3y

Putting value of y,

◓ Length of rectangle = 3(250)

◓ Length of rectangle = 3 × 250

◓ Length of rectangle = 750 cm

Also,

◓ Breadth of rectangle = 2y

Putting value of y,

◓ Breadth of rectangle = 2(250)

◓ Breadth of rectangle = 2 × 250

◓ Breadth of rectangle = 500 cm

• Henceforth, length and breadth of rectangle are 750 cm and 500 cm.

Verification,

➻ Perimeter of rectangle = 2(L + B)

➻ 2500 = 2(750 + 500)

➻ 2500 = 2(1250)

➻ 2500 = 2 × 1250

➻ 2500 = 2500

➻ LHS = RHS

• Hence, Verified ✔

Extra information,

• Perimeter of any figure is calculated by sum of it's all sides.
• Perimeter of square = 4 × side
• Perimeter of circle = 2πr
• Perimeter of equilateral ∆ = 3 × side
• Perimeter of rhombus = 4 × side

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