the length and the breadth of a rectangular Park are in the ratio 8: 5 .a 1.5 m wide running all around the outside of the park has an area of 594sq m . find the
dimensions of the park
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let the length and breadth be 8x and 5x.
area of rectangle EFGH=8x*5x
=40x^2
area of rectangle ABCD=(8x+3) (5x+3)
area of path=area of rectangle ABCD-area of rectangle EFGH
(8x+3) (5x+3)-40x^2=594
40x^2+24x+15x+9-40^2=594
39x+9=594
39x=594-9
x=585/39
x=15
length of park=8x=8*15=120m
breadth of park=5x=5*15=75m
I hope this answer is correct.
area of rectangle EFGH=8x*5x
=40x^2
area of rectangle ABCD=(8x+3) (5x+3)
area of path=area of rectangle ABCD-area of rectangle EFGH
(8x+3) (5x+3)-40x^2=594
40x^2+24x+15x+9-40^2=594
39x+9=594
39x=594-9
x=585/39
x=15
length of park=8x=8*15=120m
breadth of park=5x=5*15=75m
I hope this answer is correct.
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Sayyeda:
yup... it's correct. Thanx
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