The length, breadth and height of a box are in the ratio 1 : 2 : 3. Find the ratio of length of the diagonals of the faces.
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Correct option is D)
Let the length breadth and height of the cuboid be x,2x and 3x units.
The dimensions after increase are x+100100x, 2x+100200×2x, 3x+100200×3x.
i.e., 2x,6x and 9x
Original volume =x×2x×3x=6x3
Increased volume =2x×6x×9x=108x3
∴ Increase in volume =108x3−6x3=102x3
=17×6x3
=17× original volume
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