The length of a hall is 24m and its width is 16m. If the lateral surface area of the hall is two-third of the sum of the areas of the roof and floor, find its height.
Answers
Answered by
31
Answer:
6.4m
Explanation:
L=24
B=W= 16
LATERAL S.A =2/3 SUM OF ROOF AND FLOOR
2(24+16)h=2/3(2[24×16]
80h=2/3(768)
80h=512
h= 512/80
=6.4m
Answered by
81
Answer :
- The height of the hall = 6.4 m
Step-by-step explanation :
Given :
- The length of hall is 24 m and its width is 16 m
- Its lateral surface area is 2/3 of the sum of the areas of the roof and the floor.
To Find :
- Its height =?
Length of the hall= l = 24 m and its width = b = 16 m.
Let h metres be the height of the hall, then
the lateral surface area of the hall,
= 2(l + b)h
= 2(24 + 16) h m²
= 2 × 40 h m ²
= 80h m².
Sum of areas of the roof and the floor,
= l × b + l × b
= 2lb
= 2 x 24 x 16 m²
= 768 m².
According to given,
⟹ 80h=2/3 × 768
⟹ 80h = 512
⟹ h = 512/80 =32/5 = 6.4
Hence, the height of the hall = 6.4 m.
Similar questions
English,
5 months ago
Math,
5 months ago
English,
5 months ago
Social Sciences,
9 months ago
Math,
1 year ago