Question

The length of a hall is 24m and its width is 16m. If the lateral surface area of the hall is two-third of the sum of the areas of the roof and floor, find its height.

Answer 1

Answer:

6.4m

Explanation:

L=24

B=W= 16

LATERAL S.A =2/3 SUM OF ROOF AND FLOOR

2(24+16)h=2/3(2[24×16]

80h=2/3(768)

80h=512

h= 512/80

=6.4m

Answer 2

Answer :

• The height of the hall = 6.4 m

Step-by-step explanation :

Given :

• The length of hall is 24 m and its width is 16 m

• Its lateral surface area is 2/3 of the sum of the areas of the roof and the floor.

To Find :

• Its height =?

Length of the hall= l = 24 m and its width = b = 16 m.

Let h metres be the height of the hall, then

the lateral surface area of the hall,

= 2(l + b)h

= 2(24 + 16) h m²

= 2 × 40 h m ²

= 80h m².

Sum of areas of the roof and the floor,

= l × b + l × b

= 2lb

= 2 x 24 x 16 m²

= 768 m².

According to given,

⟹ 80h=2/3 × 768

⟹ 80h = 512

⟹ h = 512/80 =32/5 = 6.4

Hence, the height of the hall = 6.4 m.