Question

the length of a rectangle exceeds its breadth by 3cm .if length and breadth each is increased by 2cm , the area of the new rectangle is 70 square cm more than the given rectangle

Answer 1

let length be ...x
breadth be...x-3

x × (x-3)=xsq.-3x. ....eq


(x+2)×(x-3+2)=(x)×(x-3)+70
x+2)×(x-1)=x sq. - 3x + 70
xsq. - x - 2=x sq. -3x+70
xsq-xsq-x+3x=70+2
2x=72
x=36
length=36
breadth=33

Answer 2

Answer:

Length = 18cm

Breadth = 15cm

Step-by-step explanation:

Let the length be (x+3)cm

breadth = x cm

Area = l x b

        = x(x+3) cm

        = (x^2 + 3x) cm

If length is increased by 2, l = (x+3+2) = (x+5)cm

  breadth is increased by 2, b = (x+2)cm

Area = l x b

        = (x+5)(x+2)

        = x^2+2x+5x+10

        = x^2+7x+10

A.T.Q

x^2+7x+10 = x^2+3x+70

7x-3x = 70-10

4x = 60

x = 60/4

x = 15

Length = 18cm

Breadth = 15cm