Question

The length of a rectangle is 12centimeter and it's perimeter is 42centimeter .find it's breadth and areas

Answer 1

Given

$\bold{ Length \ of \ the \ rectangle} = 12 \ cm\\\bold{ Perimeter \ of \ the \ rectangle} = 42 \ cm$

Let the breadth of the rectangle be x.

$2(Length + breadth) = 42\\2(12 + x) = 42\\12+x = 21\\x = 21-12\\x = 9$

$\boxed{\boxed{\bold{Therefore, \ the \ breadth \ of \ the \ rectangle \ is \ 9 \ cm.}}}}$

Area of the rectangle

$= Length * Breadth\\= 12 * 9 \\=\boxed{\boxed{\bold{108 cm^{2}}}}$

                                                         

Answer 2

Answer: the breadth is 9 cm and the area is 108 cm squared

Step-by-step explanation: well it is given that the length of the rectangle is 12 cm and the perimeter of the rectangle is 42 cm . now we know that perimeter is basically the sumation of the sides of the rectangle and the formula for calculating the perimeter of a rectangle is 2(l+b) where l is the length and b is the breadth so since the perimeter is 42 cm

so we acn form a linear equation 2(l+b) = 42 and since we know the length we get 2(12+b)= 42 so by calculating the breadth is 9 cm

we know that to find the area of the rectangle we will apply the formula l * b where l and b are length and breadth respectively so by calculating l * b ie 12 * 9 we get the area as 108 cm squared