Question

The length of a rectangle is 24 m. Its width is 8 m less than the length. What is its area? What is its perimeter?​

Answer 1

Answer:

If 24 m is the length of a rectangle and if its width is 8m less than the length, then its area

is $384 m^{2}$ and the perimeter is 80 m

Step-by-step explanation:

Given

Length of the rectangle (L)= 24m

Given

Width (W) = 24-8 = 16m

So area = L * W

= 24*16

$= 384 m^{2}$

Perimeter = 2 (L+W)

= 2(24+16)

= 2*40

= 80 m

So the area of the rectangle is $384 m^{2}$ and the perimeter is 80m

Answer 2

To find : area and perimeter of rectangle .

Given :  length of a rectangle is 24 m. Its width is 8 m less than the length.

Solution :

• As per given data we know that length of a rectangle is 24 m. Its width is 8 m less than the length.  
• Therefore , length = $24\ cm$ and width = $(24-8 )\ m = 16\ m$ .
• To find area we use following formula -
• Area of rectangle $=l \times b$

                                     $= 24\times16$

                                     $= 384\ m^{2}$

• Perimeter of rectangle = $2 ( l+ b )$

                                                $= 2( 24 + 16 )\\= 2\times 40\\= 80\ m$

Hence ,area of rectangle is $384\ m^{2}$  and  perimeter of  rectangle is $80\ m$  .