the length of a rectangle is 27m longer than its breadth .if the perimeter of the rectangle is 110m,find its area
Answers
Answered by
6
HEY MATE HERE IS UR ANSWER
☆____________________________☆
LET THE BREADTH OF RECTANGLE BE x m.
Given:
Length: x+27
FORMULA TO BE USED:
Perimeter of rectangle=2(l+b)
Perimeter of rectangle= l*b
IMPLEMENTATION:
110=2(x+27+x)
2(2x+27)=110
2x+27=55
2x=55-27
2x=28
x=14 m(breadth)
Length= x+27= 14+ 27=41m
∴ AREA: l*b = 14 *41 =574m²
☆____________________________☆
LET THE BREADTH OF RECTANGLE BE x m.
Given:
Length: x+27
FORMULA TO BE USED:
Perimeter of rectangle=2(l+b)
Perimeter of rectangle= l*b
IMPLEMENTATION:
110=2(x+27+x)
2(2x+27)=110
2x+27=55
2x=55-27
2x=28
x=14 m(breadth)
Length= x+27= 14+ 27=41m
∴ AREA: l*b = 14 *41 =574m²
Answered by
2
let breadth be x and length be 27+x.
2[(27+x)+x]=110 m
(27+x)+(x)=110/2
27+2 x=55
2x=55-27
2x=28
x=28/2
x=14
Similar questions