the length of a rectangle is 27m longer than its breadth .if the perimeter of the rectangle is 110m,find its area
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Answered by
17
L= 27+b
perimeter = 2(27+b+b)
55=27+2b
28=2b
14m=b
L=27+14
L=41m
area=lb
=41×14
=574m^2
perimeter = 2(27+b+b)
55=27+2b
28=2b
14m=b
L=27+14
L=41m
area=lb
=41×14
=574m^2
harshitab25805:
welcome
Answered by
8
let length =x+27
breadth=x
perimeter =2(l+b)
110 = 2(x+27 +x)
110 = 2 ×(27+2x)
110 = 2×27 +2×2x
110 = 54+4x
110 = 58x
110÷58=x
1.9 = x
b =1.9
l= 1.9+ 27
l= 28.9
area = l×b =28.9×1.9=54.91m sqare (approx)
l hope it will help u
breadth=x
perimeter =2(l+b)
110 = 2(x+27 +x)
110 = 2 ×(27+2x)
110 = 2×27 +2×2x
110 = 54+4x
110 = 58x
110÷58=x
1.9 = x
b =1.9
l= 1.9+ 27
l= 28.9
area = l×b =28.9×1.9=54.91m sqare (approx)
l hope it will help u
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