Question

The length of a rectangle is 3 cm more than its width. The perimeter of the rectangle is 26cm. Find its length. please be fast

Answer 1

Answer:

Let breadth be ( x ) cm and Length be ( x + 3 ) cm

Perimeter = 24

We Know, perimeter of rectangle = 2(length + breadth )

On applying formula, we get,

2 ( x + x + 3 ) = 24

2x + 3 = 13

2x = 10

x = 5

Hence, Length =( x + 3 ) =>( 5 + 3 ) = 8 cm

Answer 2

Given :

• Length of Rectangle is 3cm more than its width.
• Perimeter of Rectangle is 26cm.

To Find :

• Length of Rectangle.

Solution :

$\longmapsto\tt{Let\:Width\:be=x}$

If length of rectangle is 3cm more than its width.So ,

$\longmapsto\tt{Length\:of\:Rectangle=x+3}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{26=2(x+3+x)}$

$\longmapsto\tt{\cancel\dfrac{26}{2}=2x+3}$

$\longmapsto\tt{13-3=2x}$

$\longmapsto\tt{10=2x}$

$\longmapsto\tt{x=\cancel\dfrac{10}{2}}$

$\longmapsto\tt\bold{x=5}$

Value of x is 5..

Therefore :

$\longmapsto\tt{Length\:of\:Rectangle=5+3}$

$\longmapsto\tt\bold{8cm}$

$\longmapsto\tt\bold{Width\:of\:Rectangle=5cm}$

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• Area of Rectangle = length × breadth
• Perimeter of Rectangle = 2(l+b)
• Area of Square = (Side)²
• Perimeter of Square = 4 × Side

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