Question

The length of a rectangle is 4 m more than the breadth. If the perimeter of the
rectangle is 84 m, find its area.

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Answer 1

Answer:

MARK IT BRAINLIST PLEASE

Answer 2

Step-by-step explanation:

Given :-

The length of a rectangle is 4 m more than the breadth. If the perimeter of the rectangle is 84 m.

To find :-

Find its area ?

Solution :-

Let the breadth of the rectangle be X m

Then, The length of the rectangle

= 4 m more than the breadth

= (X+4) m

We know that

The perimeter of a rectangle = 2(l+b) units

=> Perimeter of the given rectangle

=> 2(X+4+X) m

=> 2(2X+4) m

=>( 4X + 8 ) m

According to the given problem

Perimeter of the given rectangle = 84 m

=> 4X+8 = 84

=> 4X = 84-8

=> 4X = 76

=> X = 76/4

=> X = 19 m

Breadth of the rectangle = 19 m

Length of the rectangle = X+4 = 19+4 = 23 m

We know that

Area of a rectangle = length×breadth sq.units

=> Area = 23×19 sq.m

=> Area = 437 sq.m

Answer :-

Area of the given rectangle = 437 sq.m

Check :-

Length = 23 m

Breadth = 19 m

Length = 23 = 19+4

Length = breadth + 4 m

and

Perimeter = 2(23+19)

=> Perimeter = 2(42)=84 m

Verified the given relations in the given problem.

Used formulae:-

• The perimeter of a rectangle = 2(l+b) units

• Area of a rectangle = length×breadth sq.units

Where , l = length of the rectangle

and ,b = breadth of the rectangle