Math, asked by trenton0c, 10 hours ago

The length of a rectangle is 4 times its width. If the area of the rectangle is 362 yd2, find its perimeter.

Answers

Answered by loidphilip914

0

Answer:

A=wl

P=2(l+w)

Solving forP

P=2l+2A

l=2·4+2·362

4=189yd

Step-by-step explanation:

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