the length of a rectangle is 5cm less than twice its breath . if the length is decreased by 3 cm and breath increased by 2 cm, ,the perimeter of the resulting rectangle is 72 cm .find the area of the original rectangle
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Let L & W be the original length and width:
:Length of a rectangle is 5 cm less then twice its breadth,L = 2W - 5if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.2(L-3) + 2(W+2) = 72Divide equation by 2L - 3 + W + 2 = 36L + W - 1 = 36L + W = 37Replace L with (2W-5)(2W-5) + W = 373W = 37 + 53W = 42W = 42/3W = 14 cm is the original widthFind LL = 2(14) - 5L = 28 - 5L = 23 cm is the original length: area of original rectangle.23 * 14 = 322 sq cm
Let L & W be the original length and width:
:Length of a rectangle is 5 cm less then twice its breadth,L = 2W - 5if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.2(L-3) + 2(W+2) = 72Divide equation by 2L - 3 + W + 2 = 36L + W - 1 = 36L + W = 37Replace L with (2W-5)(2W-5) + W = 373W = 37 + 53W = 42W = 42/3W = 14 cm is the original widthFind LL = 2(14) - 5L = 28 - 5L = 23 cm is the original length: area of original rectangle.23 * 14 = 322 sq cm
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