The length of a rectangle is 6cm more than its width and the area is 72cm^2. Find the length and width.
Answers
Step-by-step explanation:
let the width of rectangle be = x
then the length of rectangle be =6x ( as the length is 6cm more than it's breadth)
area of rectangle= length(l) ×width(w)
72cm^2 = 6x × x
x= 72/6
x= 12 cm
Width =x=12 cm
length = 6x = 6×12 = 72
Answer:
The length of rect. is 12 cm and the width is 6 cm .
Step-by-step explanation:
Let the width of rectangle be x cm
then the length be ( x + 6 ) cm
A/q
Area of rect. = 72 cm ^2
=> L × B = 72
=> x ( x + 6 ) = 72
=> x^2 + 6x = 72
=> x^2 + 6x - 72 = 0
=> x^2 + 12x - 6x - 72 = 0
=> x ( x + 12 ) - 6 ( x + 12 ) = 0
=> ( x + 12 ) ( x - 6 ) = 0
here, x = -12 or 6
Since , the width of rect. cannot be negative .
So, Width = x = 6
And , length = x + 6
= 6 + 6
= 12
Hence,
The length of rect. is 12cm and
width is 6 cm .